\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
here it is again!
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
cnnd (5 Posts)
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land of crumpets
https://cnnd.dev
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full-stack dev, enthusiast of rare fish
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5 posts
bait and switch! #Whatever #Video
Dheirya_Tyagi_CEO and 1 others commented on this
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bait and switch! #Whatever #Video
little bit of silly humour
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joemama ~ October 24
No way we got the real Simon Stevin up in here
Dheirya_Tyagi_CEO ~ October 24
Cubiqé Formulae https://math.vanderbilt.edu/schectex/courses/cubic/